WEBVTT Kind: captions Language: en 00:00:00.320 --> 00:00:02.429 align:start position:0% There<00:00:00.560> are<00:00:00.719> many<00:00:01.040> methods<00:00:01.439> for<00:00:01.680> factoring 00:00:02.429 --> 00:00:02.439 align:start position:0% There are many methods for factoring 00:00:02.439 --> 00:00:05.710 align:start position:0% There are many methods for factoring tromials.<00:00:03.439> When<00:00:03.679> a<00:00:03.840> tromial<00:00:04.560> has<00:00:04.720> the<00:00:04.960> form 00:00:05.710 --> 00:00:05.720 align:start position:0% tromials. When a tromial has the form 00:00:05.720 --> 00:00:10.709 align:start position:0% tromials. When a tromial has the form x^2<00:00:06.720> +<00:00:07.200> b<00:00:07.520> x<00:00:08.160> +<00:00:08.480> c,<00:00:09.360> it's<00:00:09.679> also<00:00:09.920> said<00:00:10.160> to<00:00:10.320> have<00:00:10.480> a 00:00:10.709 --> 00:00:10.719 align:start position:0% x^2 + b x + c, it's also said to have a 00:00:10.719 --> 00:00:13.430 align:start position:0% x^2 + b x + c, it's also said to have a lead<00:00:11.120> coefficient<00:00:11.679> of<00:00:11.920> one.<00:00:12.639> This<00:00:12.880> is<00:00:13.040> because 00:00:13.430 --> 00:00:13.440 align:start position:0% lead coefficient of one. This is because 00:00:13.440 --> 00:00:15.190 align:start position:0% lead coefficient of one. This is because the<00:00:13.759> coefficient<00:00:14.320> of<00:00:14.480> the<00:00:14.639> term<00:00:14.880> with<00:00:15.040> the 00:00:15.190 --> 00:00:15.200 align:start position:0% the coefficient of the term with the 00:00:15.200 --> 00:00:18.150 align:start position:0% the coefficient of the term with the highest<00:00:15.599> power<00:00:16.000> is<00:00:16.320> 1.<00:00:17.199> When<00:00:17.520> factoring<00:00:18.000> a 00:00:18.150 --> 00:00:18.160 align:start position:0% highest power is 1. When factoring a 00:00:18.160 --> 00:00:20.550 align:start position:0% highest power is 1. When factoring a tromial<00:00:18.880> in<00:00:19.119> this<00:00:19.359> form,<00:00:20.000> the<00:00:20.240> first<00:00:20.400> thing 00:00:20.550 --> 00:00:20.560 align:start position:0% tromial in this form, the first thing 00:00:20.560 --> 00:00:22.390 align:start position:0% tromial in this form, the first thing you<00:00:20.800> have<00:00:20.880> to<00:00:21.039> do<00:00:21.359> is<00:00:21.600> make<00:00:21.760> sure<00:00:21.920> the<00:00:22.160> terms 00:00:22.390 --> 00:00:22.400 align:start position:0% you have to do is make sure the terms 00:00:22.400 --> 00:00:24.470 align:start position:0% you have to do is make sure the terms are<00:00:22.560> placed<00:00:22.880> in<00:00:23.119> descending<00:00:23.760> exponential 00:00:24.470 --> 00:00:24.480 align:start position:0% are placed in descending exponential 00:00:24.480 --> 00:00:26.630 align:start position:0% are placed in descending exponential order.<00:00:25.439> This<00:00:25.600> means<00:00:25.840> that<00:00:26.000> you<00:00:26.240> should<00:00:26.400> start 00:00:26.630 --> 00:00:26.640 align:start position:0% order. This means that you should start 00:00:26.640 --> 00:00:28.870 align:start position:0% order. This means that you should start with<00:00:26.880> the<00:00:27.039> highest<00:00:27.439> power,<00:00:28.160> then<00:00:28.400> descend 00:00:28.870 --> 00:00:28.880 align:start position:0% with the highest power, then descend 00:00:28.880 --> 00:00:31.669 align:start position:0% with the highest power, then descend from<00:00:29.119> there.<00:00:29.439> Our<00:00:30.400> final<00:00:30.800> answer<00:00:31.199> will<00:00:31.519> have 00:00:31.669 --> 00:00:31.679 align:start position:0% from there. Our final answer will have 00:00:31.679 --> 00:00:34.150 align:start position:0% from there. Our final answer will have two<00:00:31.920> sets<00:00:32.239> of<00:00:32.399> parentheses<00:00:33.040> with<00:00:33.360> x<00:00:33.680> as<00:00:33.920> the 00:00:34.150 --> 00:00:34.160 align:start position:0% two sets of parentheses with x as the 00:00:34.160 --> 00:00:36.229 align:start position:0% two sets of parentheses with x as the first<00:00:34.399> term<00:00:34.640> in<00:00:34.880> each<00:00:35.440> since<00:00:35.680> that<00:00:35.920> is<00:00:36.079> the 00:00:36.229 --> 00:00:36.239 align:start position:0% first term in each since that is the 00:00:36.239 --> 00:00:38.190 align:start position:0% first term in each since that is the only<00:00:36.480> way<00:00:36.559> to<00:00:36.800> end<00:00:37.040> up<00:00:37.280> with 00:00:38.190 --> 00:00:38.200 align:start position:0% only way to end up with 00:00:38.200 --> 00:00:40.950 align:start position:0% only way to end up with x^2.<00:00:39.200> Determining<00:00:39.760> the<00:00:40.079> other<00:00:40.239> term<00:00:40.480> in<00:00:40.719> each 00:00:40.950 --> 00:00:40.960 align:start position:0% x^2. Determining the other term in each 00:00:40.960 --> 00:00:44.069 align:start position:0% x^2. Determining the other term in each set<00:00:41.120> of<00:00:41.360> parenthesis<00:00:42.079> requires<00:00:42.640> some<00:00:43.079> work. 00:00:44.069 --> 00:00:44.079 align:start position:0% set of parenthesis requires some work. 00:00:44.079 --> 00:00:47.590 align:start position:0% set of parenthesis requires some work. Since<00:00:44.399> the<00:00:44.640> constant<00:00:45.120> term<00:00:45.520> is<00:00:46.200> pos8,<00:00:47.200> we<00:00:47.440> need 00:00:47.590 --> 00:00:47.600 align:start position:0% Since the constant term is pos8, we need 00:00:47.600 --> 00:00:50.470 align:start position:0% Since the constant term is pos8, we need to<00:00:47.760> find<00:00:48.160> factors<00:00:48.559> of<00:00:48.879> 18<00:00:49.600> or<00:00:49.920> pairs<00:00:50.239> of 00:00:50.470 --> 00:00:50.480 align:start position:0% to find factors of 18 or pairs of 00:00:50.480 --> 00:00:53.830 align:start position:0% to find factors of 18 or pairs of numbers<00:00:50.800> we<00:00:51.039> can<00:00:51.280> multiply<00:00:51.760> to<00:00:51.920> get<00:00:52.520> 18.<00:00:53.520> To 00:00:53.830 --> 00:00:53.840 align:start position:0% numbers we can multiply to get 18. To 00:00:53.840 --> 00:00:55.910 align:start position:0% numbers we can multiply to get 18. To determine<00:00:54.239> which<00:00:54.559> pair<00:00:54.800> of<00:00:54.960> factors<00:00:55.360> works, 00:00:55.910 --> 00:00:55.920 align:start position:0% determine which pair of factors works, 00:00:55.920 --> 00:00:58.470 align:start position:0% determine which pair of factors works, we<00:00:56.160> need<00:00:56.320> to<00:00:56.480> look<00:00:56.640> at<00:00:56.800> the<00:00:57.039> middle<00:00:57.399> term. 00:00:58.470 --> 00:00:58.480 align:start position:0% we need to look at the middle term. 00:00:58.480 --> 00:01:01.510 align:start position:0% we need to look at the middle term. Since<00:00:58.800> the<00:00:59.039> middle<00:00:59.280> term<00:00:59.680> is<00:01:00.079> 9x,<00:01:01.039> we<00:01:01.280> need 00:01:01.510 --> 00:01:01.520 align:start position:0% Since the middle term is 9x, we need 00:01:01.520 --> 00:01:05.590 align:start position:0% Since the middle term is 9x, we need factors<00:01:01.920> of<00:01:02.160> 18<00:01:02.719> that<00:01:03.039> add<00:01:03.359> to<00:01:03.640> 9.<00:01:04.640> Since<00:01:05.040> 3<00:01:05.280> and 00:01:05.590 --> 00:01:05.600 align:start position:0% factors of 18 that add to 9. Since 3 and 00:01:05.600 --> 00:01:09.670 align:start position:0% factors of 18 that add to 9. Since 3 and 6<00:01:05.920> multiply<00:01:06.400> to<00:01:06.640> 18<00:01:07.360> and<00:01:07.760> add<00:01:08.080> to<00:01:08.240> 9,<00:01:09.200> we<00:01:09.439> can 00:01:09.670 --> 00:01:09.680 align:start position:0% 6 multiply to 18 and add to 9, we can 00:01:09.680 --> 00:01:11.350 align:start position:0% 6 multiply to 18 and add to 9, we can try<00:01:09.840> them<00:01:10.080> as<00:01:10.240> the<00:01:10.479> values<00:01:10.799> to<00:01:10.960> fill<00:01:11.200> the 00:01:11.350 --> 00:01:11.360 align:start position:0% try them as the values to fill the 00:01:11.360 --> 00:01:13.910 align:start position:0% try them as the values to fill the blanks<00:01:11.600> in<00:01:11.760> the<00:01:12.280> parenthesis.<00:01:13.280> Now,<00:01:13.600> let's 00:01:13.910 --> 00:01:13.920 align:start position:0% blanks in the parenthesis. Now, let's 00:01:13.920 --> 00:01:16.870 align:start position:0% blanks in the parenthesis. Now, let's multiply<00:01:14.400> them<00:01:14.560> out<00:01:14.799> to<00:01:14.960> check.<00:01:15.840> It<00:01:16.080> works. 00:01:16.870 --> 00:01:16.880 align:start position:0% multiply them out to check. It works. 00:01:16.880 --> 00:01:18.630 align:start position:0% multiply them out to check. It works. You<00:01:17.119> can<00:01:17.280> always<00:01:17.600> check<00:01:17.840> your<00:01:18.080> answer<00:01:18.320> to<00:01:18.479> a 00:01:18.630 --> 00:01:18.640 align:start position:0% You can always check your answer to a 00:01:18.640 --> 00:01:20.710 align:start position:0% You can always check your answer to a factoring<00:01:19.200> problem<00:01:19.520> by<00:01:19.759> multiplying<00:01:20.400> and 00:01:20.710 --> 00:01:20.720 align:start position:0% factoring problem by multiplying and 00:01:20.720 --> 00:01:23.720 align:start position:0% factoring problem by multiplying and simplifying.